To ensure that there is a blank line between output paragraphs, set the output record separator to two newlines. The output paragraphs will not be separated since the output separator remains a single newline.
#REGEX CURLY BRACKETS CODE#
And post code of what you have, a complete working piece of code. Please give example about what your expected output should be. Now, your question is not clear or specific, since you have nested brackets.
#REGEX CURLY BRACKETS PLUS#
If RS is null, then records are separated by sequences consisting of a plus one or more blank lines, leading or trailing blank lines shall not result in empty records at the beginning or end of the input, and a shall always be a field separator, no matter what the value of FS is. this regexp will give you the text inside curly brackets. If any field in an record contains /host_name yyyyyyyyy991/ print the record. RS= changes the input record separator from a newline to blank lines. A, -after-context=NUM print NUM lines of trailing contextĪnother solution in case the file config.dat is not standard, meaning the key word "yyyyyyyyy991" doen't follow the same pattern in every section, then awk can do what you want as follows: awk -v RS='' '/host_name yyyyyyyyy991/' config.dat B, -before-context=NUM print NUM lines of leading context Meaning you only have one line before yyyyyyyyy991 and five lines after it, then this command will help you to get the output you want: grep -B 1 -A 5 "yyyyyyyyy991" config.dat Let's say your configuration file is called config.dat and it has standard format.
The syntaxs for matching are infrom of alphanumeric or metadata used to compare some strings. They are usually used to find certain patterns of characters within strings.
#REGEX CURLY BRACKETS SERIES#
The script itself simply prints any records matching the desired pattern. Regex including curly brackets Ask Question Asked 5 years, 6 months ago Modified 5 years, 6 months ago Viewed 20k times 4 I have an e-mail processing class which takes the HTML content of e-mails, and stores them in rich text fields to be later rendered as PDF's to be printed via VisualForce. Regular expressions, or regex for short, are a series of special characters that define a search pattern. Then, the -ne means "Read each input record and apply the script given by -e to it".
The -00 tells perl to read the input file as paragraphs, so each record is a paragraph (defined by 2 consecutive \n characters) instead of a line. Personally, however, I would do this sort of thing using perl's paragraph mode: $ perl -00 -ne 'print if /yyyyyyyyy991/' file The regular expression looks for the word define, followed by 0 or more non- } characters ( *), then host_name yyyyyyyyy991 and then everything until the first } (. Interpret PATTERN as an extended regular expression (ERE, see below). Print only the matched (non-empty) parts of a matching line, with each null option, this option can be used with commands like sort -z to
Zero byte (the ASCII NUL character) instead of a newline. Treat input and output data as sequences of lines, each terminated by a 'elephant'.match(/abcd/) // -> matches 'a' You can use the metacharacter to negate what is between the. Any individual character between the brackets will match, and you can also use a hyphen to define a set. Brackets indicate a set of characters to match.
The grep options used are (from the man page of GNU grep): -z, -null-data In this part we will just look at one group of symbols in depth, the brackets. Hostgroups +bu-automotiveprd,screen-automotiveprd2 The first example does not have at least 2 os that is why we got an empty list.If your grep supports it, you can use the -z option to make it slurp the entire file: $ grep -ozE 'define*host_name yyyyyyyyy991.+?}.' file P’ will match any hello which has os between 2 to 3 at the end. Curly braces matches exactly the specified number of occurrences.
0 kommentar(er)
